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Problem 14.20.

Determine the values of K_{p} that correspond to the following
values of K_{c}.

(**a**) CO(*g*) + Cl_{2}(*g*)COCl_{2}(*g*)

K_{c} = 1.2×10^{3} at 668 K

(**b**) 2 NO(*g*) + Br_{2}(*g*)2 NOBr(*g*)

K_{c} = 1.32×10^{–2} at 1000 K

(**c**) 2 COF_{2}(*g*)CO_{2}(*g*)
+ CF_{4}(*g*)

K_{c} = 2.00 at 1000 ^{o}C

Use the relationship K_{p} = K_{c}(RT)^{n}

(**a**) n = 1 – 2 = –1, so K_{p}
= 1.2×10^{3}(0.0821×668)^{–1} = 22

(**b**) n = 2 – 3 = –1, so K_{p}
= 1.32×10^{–2}(0.0821×1000)^{–1} = 1.61×10^{–4}

(**c**) n = 2 – 2 = 0, T = 1000 + 273
= 1273 K so K_{p} = 2.00(0.0821×1273)^{0} = 2.00