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Which has the lower pH, 0.00048 M H2SO4 or a vinegar solution having pH = 2.42?
The first hydrogen atom in sulfuric acid is 100% ionized but the second is not. However, if the second hydrogen atom also were 100% ionized, then [H3O+] = 2×0.00048 = 0.00096 M giving a pH = log[H3O+] = log[0.00096] = 3.02. Thus, the pH for the sulfuric acid solution must be greater than 3.02 so the vinegar solution has the lower pH.