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J. W. Hill, R. H. Petrucci, T. W. McCreary, & S. S. Perry General Chemistry 4th edition

Problem 16.77

What is the [Zn2+] in a solution that is 0.25 M in [Zn(NH3)4]2+ and has [NH3] equal to 1.50 M?




Answer:
Zn2+(aq)
+
4 NH3(aq)
[Zn(NH3)4]2+(aq)
Initial
?
?
?
Change
?
?
?
Equilibrium
x
1.50
0.25

(Note: even though the initial conditions were not given, the problem can be solved because the equilibrium conditions are given.)

x = [Zn2+] = 1.2×10–10 M