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J. W. Hill, R. H. Petrucci, T. W. McCreary, & S. S. Perry General Chemistry 4th edition

Problem 18.37

Eocell = 1.47 V for the voltaic cell

V(s)|V2+(1 M)||Cu2+(1 M)|Cu(s)

Determine the value of EoV2+/V.






Answer:

The cell is set up at standard conditions so the question can be answered using standard potentials.

The anode reaction is:

V(s)V2+(aq) + 2 e

with Eooxidation = – Eoanode being the unknown potential.

The cathode reaction is:

Cu2+(aq) + 2 eCu(s)

with Eoreduction = Eocathode = +0.340 V from the Table of Standard Reduction Potentials.

The net reaction is:

V(s) + Cu2+(aq)V2+(aq) + Cu(s)

with a cell potential = Eocell = Eoreduction + Eooxidation = Eocathode – Eoanode

Eocell = +0.340 V – Eoanode = +1.47 V

Eoanode = EoV2+/V = 0.340 – 1.47 = –1.13 V