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Eocell = 1.47 V for the voltaic cell
V(s)|V2+(1 M)||Cu2+(1 M)|Cu(s)
Determine the value of EoV2+/V.
The cell is set up at standard conditions so the question can be answered using standard potentials.
The anode reaction is:
V(s)V2+(aq) + 2 e
with Eooxidation = Eoanode being the unknown potential.
The cathode reaction is:
Cu2+(aq) + 2 eCu(s)
with Eoreduction = Eocathode = +0.340 V from the Table of Standard Reduction Potentials.
The net reaction is:
V(s) + Cu2+(aq)V2+(aq) + Cu(s)
with a cell potential = Eocell = Eoreduction + Eooxidation = Eocathode Eoanode
Eocell = +0.340 V Eoanode = +1.47 V
Eoanode = EoV2+/V = 0.340 1.47 = 1.13 V