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J. W. Hill, R. H. Petrucci, T. W. McCreary, & S. S. Perry General Chemistry 4th edition

Problem 18.59

What is Ecell for the voltaic cell diagrammed below?

Pt|H2(g, 1 atm)|0.0025 M HCl||H+(1 M)|H2(g, 1 atm)|Pt




Answer:

Anode (oxidation) reaction: H2(g)2 H+(aq) + 2 e    Eoox = 0.000 V

Cathode (reduction) reaction: 2 H+(aq) + 2 eH2(g)    Eored = 0.000 V

Net reaction: 2 H+(aq) + H2(g)2 H+(aq) + H2(g)    Eocell = 0.000 V

Ecell = +0.15 V