Final Exam
December 21, 2000
10. A. D. Richardson, K. Hedberg, and G. M. Lucier (p. 2787-2793) measured the structures of gas-phase WF6, ReF6, OsF6, IrF6, and PtF6. The average M-F bond distances were found to be 1.829 Å, 1.829 Å, 1.828 Å, 1.839 Å, and 1.852 Å, respectively. Are these values consistent with what you would expect based on periodic trends? Why or why not? Find the LFSE for each of these complexes. How would you expect the LFSE to affect the bond lengths? Which of these complexes would you expect to be Jahn-Teller active? For those that are Jahn-Teller active, predict the mode of distortion.
Answer:
Based on the increasing Z* from W to Pt, the bond lengths should be expected to decrease from WF6 to PtF6. This prediction is not consistent with the observation.
F is a weak ligand, so all the complexes will be high spin in an octahedral environment.
Compound
Bond Length
Electron Configuration
LFSE
Jahn-Teller Active?
Distortion
WF6
1.829 Å
W6+, d0
0 Dq
t2g0eg0, No
ReF6
1.829 Å
Re6+, d1
4Dq
t2g1eg0, Yes
axial compression
OsF6
1.828 Å
Os6+, d2
8Dq
t2g2eg0, Yes
axial elongation
IrF6
1.839 Å
Ir6+, d3
12Dq
t2g3eg0, No
PtF6
1.852 Å
Pt6+, d4
6Dq
t2g3eg1, Yes
either
With increasing LFSE, it might be expected that the bond lengths would decrease from WF6 to IrF6 and then become longer for PtF6. This is not consistent with observation, either.
The best simple explanation is to use MO theory, where the t2g orbitals are mostly nonbonding and the eg orbitals are antibonding. Then, from WF6 to IrF6 there should be little change in the M-F bond length (pretty much as observed) and then a significant increase in the Pt-F since the antibonding eg orbital becomes occupied.