Final Exam

December 21, 2000

10. A. D. Richardson, K. Hedberg, and G. M. Lucier (p. 2787-2793) measured the structures of gas-phase WF6, ReF6, OsF6, IrF6, and PtF6. The average M-F bond distances were found to be 1.829 Å, 1.829 Å, 1.828 Å, 1.839 Å, and 1.852 Å, respectively. Are these values consistent with what you would expect based on periodic trends? Why or why not? Find the LFSE for each of these complexes. How would you expect the LFSE to affect the bond lengths? Which of these complexes would you expect to be Jahn-Teller active? For those that are Jahn-Teller active, predict the mode of distortion.


Answer:

Based on the increasing Z* from W to Pt, the bond lengths should be expected to decrease from WF6 to PtF6. This prediction is not consistent with the observation.

F is a weak ligand, so all the complexes will be high spin in an octahedral environment.

Compound

Bond Length

Electron Configuration

LFSE

Jahn-Teller Active?

Distortion

WF6

1.829 Å

W6+, d0

0 Dq

t2g0eg0, No

ReF6

1.829 Å

Re6+, d1

–4Dq

t2g1eg0, Yes

axial compression

OsF6

1.828 Å

Os6+, d2

–8Dq

t2g2eg0, Yes

axial elongation

IrF6

1.839 Å

Ir6+, d3

–12Dq

t2g3eg0, No

PtF6

1.852 Å

Pt6+, d4

–6Dq

t2g3eg1, Yes

either

With increasing LFSE, it might be expected that the bond lengths would decrease from WF6 to IrF6 and then become longer for PtF6. This is not consistent with observation, either.

The best simple explanation is to use MO theory, where the t2g orbitals are mostly nonbonding and the eg orbitals are antibonding. Then, from WF6 to IrF6 there should be little change in the M-F bond length (pretty much as observed) and then a significant increase in the Pt-F since the antibonding eg orbital becomes occupied.