Problem 2.32
Why is (CH3)2O quite soluble in H2O
, and why is C2H6 very insoluble in H2O?
Answer:
Solubility requires an attractive interaction between the solute and
the solvent. In the case of the water/ether mixture, both molecules are
polar, allowing a dipole-dipole interaction, and the water can act as a
hydrogen bond donor to the ether O atom, leading to a quite strong attraction.
In the case of ethane/water, the only weak attraction possible between
the two molecules is the van der Waal's interaction; since both molecules
are small, this attraction is weak leading to little solubility of ethane
in water.