Problem 4.18
Apply the group theoretical treatment to obtain the bonding description
in NO2-.
Answer:
First, find the point group (C2v) and draw the axis systems
(except for z on N, this is arbitrary).
The character table (from Appendix C) is:
| C2v |
|
|
v(xz) |
'v(yz) |
||
| a1 |
|
|
|
|
z | x2, y2, z2 |
| a2 |
|
|
|
|
Rz | xy |
| b1 |
|
|
|
|
x, Ry | xz |
| b2 |
|
|
|
|
y, Rz | yz |
The irreducible representations of the N basis orbitals are found directly
from the character table as 2s (a1), 2px (b1),
2py (b2), and 2pz (a1).
The irreducible representations of the O basis orbitals, also 2s and
2p, must be found by using the symmetry:
Total representations for O orbitals:
| basis |
|
|
v(xz) |
'v(yz) |
| 2s |
|
|
|
|
| 2px |
|
|
|
|
| 2py |
|
|
|
|
| 2pz |
|
|
|
|
So the O 2s orbitals transform as a1 + b1, the
O 2px orbitals transform as a1 + b1, the
O 2py orbitals transform as a1 + b1, and
the O 2pz orbitals transform as a2 + b2.
Next, generate the group orbitals using projection operators:
| basis |
|
|
v(xz) |
'v(yz) |
| Rs1 |
|
|
|
|
| Rpx1 |
|
|
|
|
| Rpy1 |
|
|
|
|
| Rpz1 |
|
|
|
|
After normalization:
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Combining orbitals of like symmetry and energy: